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8x^2-49x-75=0
a = 8; b = -49; c = -75;
Δ = b2-4ac
Δ = -492-4·8·(-75)
Δ = 4801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-\sqrt{4801}}{2*8}=\frac{49-\sqrt{4801}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+\sqrt{4801}}{2*8}=\frac{49+\sqrt{4801}}{16} $
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